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Q21411060

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Q21411060

Summary

Q21411060 is a version, edition or translation[1].

Key Facts

  • Q21411060 authored Lord Byron[2].
  • Q21411060's instance of is recorded as version, edition or translation[3].
  • Q21411060's language of work or name is recorded as Portuguese[4].
  • Q21411060's edition or translation of is recorded as Parisina[5].
  • Q21411060's translator is recorded as Álvares de Azevedo[6].

Body

Definition and Type

Q21411060's instance of is recorded as version, edition or translation[3].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [3] ↑ . wikidata.org.
  2. [2] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.
  5. [6] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Q21411060. Retrieved May 7, 2026, from https://4ort.xyz/entity/q21411060
MLA “Q21411060.” 4ort.xyz Knowledge Graph, 4ort.xyz, 7 May. 2026, https://4ort.xyz/entity/q21411060.
BibTeX @misc{4ortxyz_q21411060_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Q21411060}}, year = {2026}, url = {https://4ort.xyz/entity/q21411060}, note = {Accessed: 2026-05-07}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Q21411060 — https://4ort.xyz/entity/q21411060 (retrieved 2026-05-07)

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