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Wizard of the Year

episode of Wizards of Waverly Place (S4 E15)
TVEpisode television_series_episode Q51127705
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Wizard of the Year

Summary

Wizard of the Year is a television series episode[1].

Key Facts

  • Wizard of the Year's instance of is recorded as television series episode[2].
  • Wizard of the Year's director is recorded as Victor Gonzalez[3].
  • Wizard of the Year's follows is recorded as Beast Tamer[4].
  • Wizard of the Year's followed by is recorded as Misfortune at the Beach[5].
  • Wizard of the Year's part of the series is recorded as Wizards of Waverly Place[6].
  • Wizard of the Year's IMDb ID is recorded as tt1912965[7].
  • Wizard of the Year's original language of film or TV show is recorded as English[8].
  • Wizard of the Year's original broadcaster is recorded as Disney Channel[9].
  • Wizard of the Year's publication date is recorded as +2011-07-08T00:00:00Z[10].
  • Wizard of the Year's title is recorded as Wizard of the Year[11].
  • Wizard of the Year's Metacritic ID is recorded as tv/wizards-of-waverly-place/season-4/episode-15-wizard-of-the-year[12].
  • Wizard of the Year's production code is recorded as 417[13].
  • Wizard of the Year's TV.com ID is recorded as shows/wizards-of-waverly-place/wizard-of-the-year-1376234[14].
  • Wizard of the Year's EIDR content ID is recorded as 10.5240/B26F-69C6-9389-62CA-91D0-1[15].
  • Wizard of the Year's OMDb film ID is recorded as 62601[16].
  • Wizard of the Year's CineMagia title ID is recorded as 703329[17].
  • Wizard of the Year's season is recorded as Wizards of Waverly Place, season 4[18].
  • Wizard of the Year's Trakt.tv ID is recorded as shows/wizards-of-waverly-place/seasons/4/episodes/15[19].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.
  5. [6] ↑ . wikidata.org.
  6. [7] ↑ . wikidata.org.
  7. [8] ↑ . wikidata.org.
  8. [9] ↑ . wikidata.org.
  9. [10] ↑ . wikidata.org.
  10. [11] ↑ . wikidata.org.
  11. [12] ↑ . Metacritic. Retrieved . wikidata.org.
  12. [13] ↑ . wikidata.org.
  13. [14] ↑ . wikidata.org.
  14. [15] ↑ . wikidata.org.
  15. [16] ↑ . wikidata.org.
  16. [17] ↑ . wikidata.org.
  17. [18] ↑ . wikidata.org.
  18. [19] ↑ . Trakt.tv. Retrieved . trakt.tv. Provenance: wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Wizard of the Year. Retrieved May 3, 2026, from https://4ort.xyz/entity/wizard-of-the-year
MLA “Wizard of the Year.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/wizard-of-the-year.
BibTeX @misc{4ortxyz_wizard-of-the-year_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Wizard of the Year}}, year = {2026}, url = {https://4ort.xyz/entity/wizard-of-the-year}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Wizard of the Year — https://4ort.xyz/entity/wizard-of-the-year (retrieved 2026-05-03)

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