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Wikipedia:Tim Starling Day

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Event holiday Q14360104
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Wikipedia:Tim Starling Day

Summary

Wikipedia:Tim Starling Day is a holiday[1].

Key Facts

  • Wikipedia:Tim Starling Day's instance of is recorded as holiday[2].
  • Wikipedia:Tim Starling Day's instance of is recorded as Wikimedia project page[3].
  • Tim Starling is named after Wikipedia:Tim Starling Day[4].
  • +2003-10-31T00:00:00Z marks the founding of Wikipedia:Tim Starling Day[5].
  • Wikipedia:Tim Starling Day's day in year for periodic occurrence is recorded as October 31[6].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.
  5. [6] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Wikipedia:Tim Starling Day. Retrieved May 3, 2026, from https://4ort.xyz/entity/wikipedia-tim-starling-day
MLA “Wikipedia:Tim Starling Day.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/wikipedia-tim-starling-day.
BibTeX @misc{4ortxyz_wikipedia-tim-starling-day_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Wikipedia:Tim Starling Day}}, year = {2026}, url = {https://4ort.xyz/entity/wikipedia-tim-starling-day}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Wikipedia:Tim Starling Day — https://4ort.xyz/entity/wikipedia-tim-starling-day (retrieved 2026-05-03)

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