Teviot Bridge
0 sources
Teviot Bridge
Summary
Teviot Bridge is a road bridge[1].
Key Facts
- Teviot Bridge is located in Scottish Borders[2].
- Teviot Bridge is located in Kelso[3].
- Teviot Bridge is in the country of United Kingdom[4].
- Teviot Bridge's image is recorded as Teviot Bridge near Kelso - geograph.org.uk - 368629.jpg[5].
- Teviot Bridge's instance of is recorded as road bridge[6].
- Teviot Bridge's crosses is recorded as River Teviot[7].
- Teviot Bridge's location is recorded as Kelso[8].
- Teviot Bridge's Structurae structure ID is recorded as 20021671[9].
- +1795-00-00T00:00:00Z marks the founding of Teviot Bridge[10].
- Teviot Bridge's OS grid reference is recorded as NT7198433547[11].
- Teviot Bridge's coordinate location is recorded as {'globe': 'http://www.wikidata.org/entity/Q2', 'altitude': None, 'latitude': 55.5947, 'longitude': -2.44611, 'precision': 1e-06}[12].
- Teviot Bridge's Historic Environment Scotland ID is recorded as LB35847[13].
- Teviot Bridge's Canmore ID is recorded as 77552[14].
- Teviot Bridge's heritage designation is recorded as category A listed building[15].
- Teviot Bridge's carries thoroughfare is recorded as A699 road[16].
- Teviot Bridge's Google Knowledge Graph ID is recorded as /g/11c0q_c9ct[17].
- Teviot Bridge's associated electoral district is recorded as Berwickshire, Roxburgh and Selkirk[18].
- Teviot Bridge's historic county is recorded as Roxburghshire[19].
- Teviot Bridge's GB1900 ID is recorded as 5819ffb32c66dc8e69006fc7[20].
- Teviot Bridge's British Listed Buildings ID is recorded as 200380518[21].
Body
Geography
Teviot Bridge is in the country of United Kingdom[4]. Located in include Scottish Borders[2], a council area[22], in United Kingdom[23], founded in 1975[24] and Kelso[3], a civil parish[25], in United Kingdom[26].
Designation and Status
Teviot Bridge's instance of is recorded as road bridge[6]. Its heritage designation is recorded as category A listed building[15].
History and Context
+1795-00-00T00:00:00Z marks the founding of Teviot Bridge[10].