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Template:Taxonomy/Asparagaceae

taxonomy template
Intangible taxonomy_template Q10972359
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Template:Taxonomy/Asparagaceae

Summary

Template:Taxonomy/Asparagaceae is a taxonomy template[1]. Template:Taxonomy/Asparagaceae has Wikipedia articles in 11 language editions, a strong signal of global cultural recognition.[2]

Key Facts

  • Template:Taxonomy/Asparagaceae's instance of is recorded as taxonomy template[3].
  • Template:Taxonomy/Asparagaceae's template has topic is recorded as Asparagaceae[4].

Why It Matters

Template:Taxonomy/Asparagaceae has Wikipedia articles in 11 language editions, a strong signal of global cultural recognition.[2]

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [3] ↑ . wikidata.org.
  2. [4] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

Aggregate / graph-position facts

  1. [2] ↑ . Wikidata sitelinks. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Template:Taxonomy/Asparagaceae. Retrieved May 3, 2026, from https://4ort.xyz/entity/template-taxonomy-asparagaceae
MLA “Template:Taxonomy/Asparagaceae.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/template-taxonomy-asparagaceae.
BibTeX @misc{4ortxyz_template-taxonomy-asparagaceae_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Template:Taxonomy/Asparagaceae}}, year = {2026}, url = {https://4ort.xyz/entity/template-taxonomy-asparagaceae}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Template:Taxonomy/Asparagaceae — https://4ort.xyz/entity/template-taxonomy-asparagaceae (retrieved 2026-05-03)

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