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Template:OGL

Wikimedia template identifying content as licensed under the Open Government Licence v1.0
Intangible wikimedia_copyright_template Q14447982
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Template:OGL

Summary

Template:OGL is a Wikimedia copyright template[1]. Template:OGL has Wikipedia articles in 5 language editions, a strong signal of global cultural recognition.[2]

Key Facts

  • Template:OGL's instance of is recorded as Wikimedia copyright template[3].
  • Template:OGL's template has topic is recorded as Open Government Licence v1.0[4].

Why It Matters

Template:OGL has Wikipedia articles in 5 language editions, a strong signal of global cultural recognition.[2]

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [3] ↑ . wikidata.org.
  2. [4] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

Aggregate / graph-position facts

  1. [2] ↑ . Wikidata sitelinks. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Template:OGL. Retrieved May 3, 2026, from https://4ort.xyz/entity/template-ogl
MLA “Template:OGL.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/template-ogl.
BibTeX @misc{4ortxyz_template-ogl_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Template:OGL}}, year = {2026}, url = {https://4ort.xyz/entity/template-ogl}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Template:OGL — https://4ort.xyz/entity/template-ogl (retrieved 2026-05-03)

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