Home › Entities › wikimedia_subtemplate › Template:Authority control/VIAF

Template:Authority control/VIAF

Wikimedia template
Intangible wikimedia_subtemplate Q6705098
Press Enter · cited answer in seconds

Template:Authority control/VIAF

Summary

Template:Authority control/VIAF is a Wikimedia subtemplate[1].

Key Facts

  • Template:Authority control/VIAF's instance of is recorded as Wikimedia subtemplate[2].
  • Template:Authority control/VIAF's different from is recorded as Template:VIAF[3].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Template:Authority control/VIAF. Retrieved May 3, 2026, from https://4ort.xyz/entity/template-authority-control-viaf
MLA “Template:Authority control/VIAF.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/template-authority-control-viaf.
BibTeX @misc{4ortxyz_template-authority-control-viaf_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Template:Authority control/VIAF}}, year = {2026}, url = {https://4ort.xyz/entity/template-authority-control-viaf}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Template:Authority control/VIAF — https://4ort.xyz/entity/template-authority-control-viaf (retrieved 2026-05-03)

Canonical URL: https://4ort.xyz/entity/template-authority-control-viaf · Last refreshed: