Template:Academy Award for Best Adapted Screenplay

Wikimedia template
Intangible wikimedia_navigational_template Q6667517
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Template:Academy Award for Best Adapted Screenplay

Summary

Template:Academy Award for Best Adapted Screenplay is a Wikimedia navigational template[1]. It has Wikipedia articles in 18 language editions, a strong signal of global cultural recognition.[2]

Key Facts

  • Template:Academy Award for Best Adapted Screenplay's instance of is recorded as Wikimedia navigational template[3].
  • Template:Academy Award for Best Adapted Screenplay's template has topic is recorded as Academy Award for Best Writing, Adapted Screenplay[4].

Why It Matters

Template:Academy Award for Best Adapted Screenplay has Wikipedia articles in 18 language editions, a strong signal of global cultural recognition.[2]

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Template:Academy Award for Best Adapted Screenplay. Retrieved May 3, 2026, from https://4ort.xyz/entity/template-academy-award-for-best-adapted-screenplay
MLA “Template:Academy Award for Best Adapted Screenplay.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/template-academy-award-for-best-adapted-screenplay.
BibTeX @misc{4ortxyz_template-academy-award-for-best-adapted-screenplay_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Template:Academy Award for Best Adapted Screenplay}}, year = {2026}, url = {https://4ort.xyz/entity/template-academy-award-for-best-adapted-screenplay}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Template:Academy Award for Best Adapted Screenplay — https://4ort.xyz/entity/template-academy-award-for-best-adapted-screenplay (retrieved 2026-05-03)

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