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Segretissimo

Italian spy novel series
Place editorial_collection Q3954390
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Segretissimo

Summary

Segretissimo is an editorial collection[1].

Key Facts

  • Segretissimo's instance of is recorded as editorial collection[2].
  • Segretissimo's publisher is recorded as Gruppo Mondadori[3].
  • Segretissimo's genre is recorded as spy fiction[4].
  • +1961-00-00T00:00:00Z marks the founding of Segretissimo[5].
  • Segretissimo's Freebase ID is recorded as /m/05pcq48[6].
  • Segretissimo's form of creative work is recorded as novel[7].

Body

Designation and Status

Segretissimo's instance of is recorded as editorial collection[2].

History and Context

+1961-00-00T00:00:00Z marks the founding of Segretissimo[5].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.
  5. [6] ↑ . wikidata.org.
  6. [7] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Segretissimo. Retrieved May 3, 2026, from https://4ort.xyz/entity/segretissimo
MLA “Segretissimo.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/segretissimo.
BibTeX @misc{4ortxyz_segretissimo_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Segretissimo}}, year = {2026}, url = {https://4ort.xyz/entity/segretissimo}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Segretissimo — https://4ort.xyz/entity/segretissimo (retrieved 2026-05-03)

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