Schalow Pond
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Schalow Pond
Summary
Schalow Pond is a lake[1].
Key Facts
- Schalow Pond is located in Okanogan County[2].
- Schalow Pond is in the country of United States[3].
- Schalow Pond's instance of is recorded as lake[4].
- Schalow Pond's instance of is recorded as reservoir[5].
- Schalow Pond's inflows is recorded as Coulee Creek[6].
- Schalow Pond's outflows is recorded as Coulee Creek[7].
- Schalow Pond's coordinate location is recorded as {'globe': 'http://www.wikidata.org/entity/Q2', 'altitude': None, 'latitude': 48.6005485, 'longitude': -119.6772451, 'precision': 1e-07}[8].
- Schalow Pond sits at an elevation of {'unit': 'http://www.wikidata.org/entity/Q11573', 'amount': '+517'}[9].
- Schalow Pond covers an area of {'unit': 'http://www.wikidata.org/entity/Q81292', 'amount': '+6.7'}[10].
- Schalow Pond's perimeter is recorded as {'unit': 'http://www.wikidata.org/entity/Q11573', 'amount': '+675'}[11].
- Schalow Pond's located in protected area is recorded as Sinlahekin Wildlife Area[12].
- Schalow Pond's drainage basin is recorded as Okanagan Basin[13].
- Schalow Pond's impounded by is recorded as Schallow Lake Dam[14].
Body
Geography
Schalow Pond is in the country of United States[3]. It is located in Okanogan County[2].
Physical Characteristics
Schalow Pond covers an area of {'unit': 'http://www.wikidata.org/entity/Q81292', 'amount': '+6.7'}[10]. It sits at an elevation of {'unit': 'http://www.wikidata.org/entity/Q11573', 'amount': '+517'}[9].