Scarecrow

episode of Lassie (S19 E4)
TVEpisode television_series_episode Q114463943
Press Enter · cited answer in seconds

Scarecrow

Summary

Scarecrow is a television series episode[1].

Key Facts

  • Scarecrow's instance of is recorded as television series episode[2].
  • Scarecrow's director is recorded as Jack Hively[3].
  • Scarecrow's screenwriter is recorded as Eric Freiwald[4].
  • Scarecrow's follows is recorded as For Those Who Follow[5].
  • Scarecrow's followed by is recorded as A Girl and a Boy (Part 1)[6].
  • Scarecrow's part of the series is recorded as Lassie[7].
  • Scarecrow's IMDb ID is recorded as tt1274018[8].
  • Scarecrow's original language of film or TV show is recorded as English[9].
  • Scarecrow's original broadcaster is recorded as CBS[10].
  • Scarecrow's country of origin is recorded as United States[11].
  • Scarecrow's publication date is recorded as +1972-10-14T00:00:00Z[12].
  • Scarecrow's title is recorded as Scarecrow[13].
  • Scarecrow's season is recorded as Lassie, season 19[14].
  • Scarecrow's Trakt.tv ID is recorded as shows/lassie-1954/seasons/19/episodes/4[15].

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Scarecrow. Retrieved May 3, 2026, from https://4ort.xyz/entity/scarecrow-q114463943
MLA “Scarecrow.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/scarecrow-q114463943.
BibTeX @misc{4ortxyz_scarecrow-q114463943_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Scarecrow}}, year = {2026}, url = {https://4ort.xyz/entity/scarecrow-q114463943}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Scarecrow — https://4ort.xyz/entity/scarecrow-q114463943 (retrieved 2026-05-03)

Canonical URL: https://4ort.xyz/entity/scarecrow-q114463943 · Last refreshed: