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Rosa 'Queen of Sweden'

Light pink shrub rose cultivar
Taxon rose_cultivar Q4048510
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Rosa 'Queen of Sweden'

Summary

Rosa 'Queen of Sweden' is a rose cultivar[1]. Rosa 'Queen of Sweden' draws 11 Wikipedia views per month (rose_cultivar category, ranking #31 of 105).[2]

Key Facts

  • Rosa 'Queen of Sweden' is the creator of David C. H. Austin[3].
  • Rosa 'Queen of Sweden''s image is recorded as Rosa Queen of Sweden 2022-07-06 6747.jpg[4].
  • Rosa 'Queen of Sweden''s instance of is recorded as rose cultivar[5].
  • Rosa 'Queen of Sweden''s taxon rank is recorded as cultivar[6].
  • Queen Silvia of Sweden is named after Rosa 'Queen of Sweden'[7].
  • Rosa 'Queen of Sweden''s parent taxon is recorded as Rosa[8].
  • Rosa 'Queen of Sweden''s taxon name is recorded as Rosa ‘Queen of Sweden’[9].
  • Rosa 'Queen of Sweden''s Commons category is recorded as Rosa 'Queen of Sweden'[10].
  • Rosa 'Queen of Sweden''s country of origin is recorded as United Kingdom[11].
  • +2004-00-00T00:00:00Z marks the founding of Rosa 'Queen of Sweden'[12].
  • Rosa 'Queen of Sweden''s Commons gallery is recorded as Rosa 'Queen of Sweden'[13].
  • Rosa 'Queen of Sweden''s hybrid of is recorded as Rosa 'Charlotte'[14].
  • Rosa 'Queen of Sweden''s hybrid of is recorded as seedling[15].
  • Rosa 'Queen of Sweden''s name is recorded as {'lang': 'und', 'text': 'Queen of Sweden'}[16].
  • Rosa 'Queen of Sweden''s Google Knowledge Graph ID is recorded as /g/11dyk1hfv[17].
  • Rosa 'Queen of Sweden''s hardiness of plant is recorded as 6b[18].

Body

Works and Contributions

Rosa 'Queen of Sweden' is the creator of David C. H. Austin[3].

Why It Matters

Rosa 'Queen of Sweden' draws 11 Wikipedia views per month (rose_cultivar category, ranking #31 of 105).[2] Rosa 'Queen of Sweden' has Wikipedia articles in 5 language editions, a strong signal of global cultural recognition.[19]

Related Entities

Queen Silvia of Sweden United Kingdom

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [4] ↑ . wikidata.org.
  2. [5] ↑ . wikidata.org.
  3. [6] ↑ . wikidata.org.
  4. [7] ↑ . wikidata.org.
  5. [3] ↑ . wikidata.org.
  6. [8] ↑ . wikidata.org.
  7. [9] ↑ . wikidata.org.
  8. [10] ↑ . wikidata.org.
  9. [11] ↑ . wikidata.org.
  10. [12] ↑ . wikidata.org.
  11. [13] ↑ . wikidata.org.
  12. [14] ↑ . wikidata.org.
  13. [15] ↑ . wikidata.org.
  14. [16] ↑ . wikidata.org.
  15. [17] ↑ . wikidata.org.
  16. [18] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

Aggregate / graph-position facts

  1. [2] ↑ . Wikimedia Foundation. dumps.wikimedia.org.
  2. [19] ↑ . Wikidata sitelinks. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Rosa 'Queen of Sweden'. Retrieved May 3, 2026, from https://4ort.xyz/entity/rosa-queen-of-sweden
MLA “Rosa 'Queen of Sweden'.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/rosa-queen-of-sweden.
BibTeX @misc{4ortxyz_rosa-queen-of-sweden_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Rosa 'Queen of Sweden'}}, year = {2026}, url = {https://4ort.xyz/entity/rosa-queen-of-sweden}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Rosa 'Queen of Sweden' — https://4ort.xyz/entity/rosa-queen-of-sweden (retrieved 2026-05-03)

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