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Rosa 'Fragola'

rose cultivar
Taxon rose_cultivar Q83665236
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Rosa 'Fragola'

Summary

Rosa 'Fragola' is a rose cultivar[1].

Key Facts

  • Rosa 'Fragola''s instance of is recorded as rose cultivar[2].
  • Rosa 'Fragola''s taxon rank is recorded as cultivar[3].
  • Rosa 'Fragola''s parent taxon is recorded as Rosa[4].
  • Rosa 'Fragola''s taxon name is recorded as Rosa ‘Fragola’[5].
  • Rosa 'Fragola''s subclass of is recorded as hybrid tea rose[6].
  • Rosa 'Fragola''s Commons category is recorded as Rosa 'Fragola'[7].
  • Rosa 'Fragola''s name is recorded as Fragola[8].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.
  5. [6] ↑ . wikidata.org.
  6. [7] ↑ . wikidata.org.
  7. [8] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Rosa 'Fragola'. Retrieved May 3, 2026, from https://4ort.xyz/entity/rosa-fragola-
MLA “Rosa 'Fragola'.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/rosa-fragola-.
BibTeX @misc{4ortxyz_rosa-fragola-_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Rosa 'Fragola'}}, year = {2026}, url = {https://4ort.xyz/entity/rosa-fragola-}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Rosa 'Fragola' — https://4ort.xyz/entity/rosa-fragola- (retrieved 2026-05-03)

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