Roger de Breteuil, 2nd Earl of Hereford

English peer (1051-1087)
Person human Q369254
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Roger de Breteuil, 2nd Earl of Hereford

Summary

Roger de Breteuil, 2nd Earl of Hereford is a human[1]. He was born on +1056-00-00T00:00:00Z[2]. He died on +1087-01-01T00:00:00Z[3]. He worked as a feudatory[4]. He ranks in the top 0.73% of human entities by monthly Wikipedia readership (30 views/month, #7,275 of 1,000,298).[5]

Key Facts

  • Roger de Breteuil, 2nd Earl of Hereford was born on +1056-00-00T00:00:00Z[2].
  • Roger de Breteuil, 2nd Earl of Hereford died on +1087-01-01T00:00:00Z[3].
  • Roger de Breteuil, 2nd Earl of Hereford's father was William FitzOsbern, 1st Earl of Hereford[6].
  • Roger de Breteuil, 2nd Earl of Hereford's mother was Alice de Toeni[7].
  • Roger de Breteuil, 2nd Earl of Hereford held citizenship in Kingdom of England[8].
  • Roger de Breteuil, 2nd Earl of Hereford's professions included feudatory[4].
  • Roger de Breteuil, 2nd Earl of Hereford is recorded as male[9].
  • Roger de Breteuil, 2nd Earl of Hereford's instance of is recorded as human[10].
  • Roger de Breteuil, 2nd Earl of Hereford's family is recorded as Q729234[11].
  • Roger de Breteuil, 2nd Earl of Hereford's noble title is recorded as count[12].
  • Roger de Breteuil, 2nd Earl of Hereford's participated in conflict is recorded as Revolt of the Earls[13].
  • Roger de Breteuil, 2nd Earl of Hereford's Freebase ID is recorded as /m/08m634[14].
  • Roger de Breteuil, 2nd Earl of Hereford's given name is recorded as Roger[15].
  • Roger de Breteuil, 2nd Earl of Hereford's described by source is recorded as Dictionary of National Biography, 1885–1900[16].
  • Roger de Breteuil, 2nd Earl of Hereford's described by source is recorded as Encyclopædia Britannica 11th edition[17].
  • Roger de Breteuil, 2nd Earl of Hereford's Oxford Dictionary of National Biography ID is recorded as 9661[18].
  • Roger de Breteuil, 2nd Earl of Hereford's name in native language is recorded as {'lang': 'en', 'text': 'Roger de Breteuil'}[19].
  • Roger de Breteuil, 2nd Earl of Hereford's genealogics.org person ID is recorded as I00426944[20].
  • Roger de Breteuil, 2nd Earl of Hereford's Geni.com profile ID is recorded as 6000000006442592411[21].
  • Roger de Breteuil, 2nd Earl of Hereford's Kindred Britain ID is recorded as I5116[22].
  • Roger de Breteuil, 2nd Earl of Hereford's Prabook ID is recorded as 1927085[23].
  • Roger de Breteuil, 2nd Earl of Hereford's sibling is recorded as Emma de Guader, Countess of Norfolk[24].
  • Roger de Breteuil, 2nd Earl of Hereford's WeRelate person ID is recorded as Roger_de_Breteuil_(1)[25].
  • Roger de Breteuil, 2nd Earl of Hereford's Roglo person ID is recorded as p=roger;n=de+crepon[26].
  • Roger de Breteuil, 2nd Earl of Hereford's SNARC ID is recorded as Diyarbakır[27].

Body

Origins and Family

Roger de Breteuil, 2nd Earl of Hereford was born on +1056-00-00T00:00:00Z[2]. His father was William FitzOsbern, 1st Earl of Hereford[6]. His mother was Alice de Toeni[7].

Career and Affiliations

Roger de Breteuil, 2nd Earl of Hereford's professions included feudatory[4].

Death and Burial

Roger de Breteuil, 2nd Earl of Hereford died on +1087-01-01T00:00:00Z[3].

Why It Matters

Roger de Breteuil, 2nd Earl of Hereford ranks in the top 0.73% of human entities by monthly Wikipedia readership (30 views/month, #7,275 of 1,000,298).[5] He has Wikipedia articles in 9 language editions, a strong signal of global cultural recognition.[28] He is known by 3 alternative names across languages and contexts.[29]

FAQs

Who were Roger de Breteuil, 2nd Earl of Hereford's parents?

Roger de Breteuil, 2nd Earl of Hereford's father was William FitzOsbern, 1st Earl of Hereford[6]. Roger de Breteuil, 2nd Earl of Hereford's mother was Alice de Toeni[7].

What did Roger de Breteuil, 2nd Earl of Hereford do for work?

Roger de Breteuil, 2nd Earl of Hereford worked as feudatory[4].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [9] . Q75653886. wikidata.org.
  2. [6] . Q75653886. wikidata.org.
  3. [7] . Q75653886. wikidata.org.
  4. [8] . wikidata.org.
  5. [10] . wikidata.org.
  6. [11] . wikidata.org.
  7. [12] . wikidata.org.
  8. [4] . wikidata.org.
  9. [2] . wikidata.org.
  10. [3] . wikidata.org.
  11. [13] . wikidata.org.
  12. [14] . Freebase Data Dumps. wikidata.org.
  13. [15] . wikidata.org.
  14. [16] . wikidata.org.
  15. [17] . wikidata.org.
  16. [18] . wikidata.org.
  17. [19] . wikidata.org.
  18. [20] . wikidata.org.
  19. [21] . wikidata.org.
  20. [22] . wikidata.org.
  21. [23] . wikidata.org.
  22. [24] . Q75653886. wikidata.org.
  23. [25] . wikidata.org.
  24. [26] . wikidata.org.
  25. [27] . wikidata.org.

Class ancestry

  1. [1] . Wikidata. wikidata.org.

Aggregate / graph-position facts

  1. [5] . Wikimedia Foundation. dumps.wikimedia.org.
  2. [28] . Wikidata sitelinks. wikidata.org.
  3. [29] . Wikidata aliases. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Roger de Breteuil, 2nd Earl of Hereford. Retrieved April 10, 2026, from https://4ort.xyz/entity/roger-de-breteuil-2nd-earl-of-hereford
MLA “Roger de Breteuil, 2nd Earl of Hereford.” 4ort.xyz Knowledge Graph, 4ort.xyz, 10 Apr. 2026, https://4ort.xyz/entity/roger-de-breteuil-2nd-earl-of-hereford.
BibTeX @misc{4ortxyz_roger-de-breteuil-2nd-earl-of-hereford_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Roger de Breteuil, 2nd Earl of Hereford}}, year = {2026}, url = {https://4ort.xyz/entity/roger-de-breteuil-2nd-earl-of-hereford}, note = {Accessed: 2026-04-10}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Roger de Breteuil, 2nd Earl of Hereford — https://4ort.xyz/entity/roger-de-breteuil-2nd-earl-of-hereford (retrieved 2026-04-10)

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