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Rob Roy (Scott)

Polish edition of Walter Scott's novel
CreativeWork version_edition_or_translation Q28732447

Facts

10 properties
Instance of
version, edition or translation, edition of a translation[3]
Author
Walter Scott[2]
Language of work or name
Polish[5]
Publication date
1875[6]
Copyright status
public domain, public domain[10][11]
Edition or translation of
Rob Roy[7]
Imported from
wholeness_audit_2026-05-02
Place of publication
Warsaw[4]
Title
Rob-Roy[9]
Translator
Michał Grubecki[8]
🏷️ Also known as
en Rob Roy (Scott) pl Rob-Roy
🔖 Identifiers · 1
Wikisource index page URL
pl.wikisource.org

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Summary

Rob Roy (Scott) is a version, edition or translation[1].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [3] ↑ . wikidata.org.
  2. [2] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.
  5. [6] ↑ . wikidata.org.
  6. [7] ↑ . wikidata.org.
  7. [8] ↑ . wikidata.org.
  8. [9] ↑ . wikidata.org.
  9. [10] ↑ . wikidata.org.
  10. [11] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

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Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Rob Roy (Scott). Retrieved May 3, 2026, from https://4ort.xyz/entity/rob-roy-scott-
MLA “Rob Roy (Scott).” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/rob-roy-scott-.
BibTeX @misc{4ortxyz_rob-roy-scott-_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Rob Roy (Scott)}}, year = {2026}, url = {https://4ort.xyz/entity/rob-roy-scott-}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Rob Roy (Scott) — https://4ort.xyz/entity/rob-roy-scott- (retrieved 2026-05-03)

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