Home › Entities › wikimedia_disambiguation_page › Ramallo

Ramallo

Wikimedia disambiguation page
DisambiguationPage wikimedia_disambiguation_page Q397099
Press Enter · cited answer in seconds

Ramallo

Summary

Ramallo is a Wikimedia disambiguation page[1]. Ramallo has Wikipedia articles in 7 language editions, a strong signal of global cultural recognition.[2]

Key Facts

  • Ramallo's instance of is recorded as Wikimedia disambiguation page[3].
  • Ramallo's different from is recorded as Ramallo[4].

Why It Matters

Ramallo has Wikipedia articles in 7 language editions, a strong signal of global cultural recognition.[2]

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [3] ↑ . wikidata.org.
  2. [4] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

Aggregate / graph-position facts

  1. [2] ↑ . Wikidata sitelinks. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Ramallo. Retrieved April 10, 2026, from https://4ort.xyz/entity/ramallo-q397099
MLA “Ramallo.” 4ort.xyz Knowledge Graph, 4ort.xyz, 10 Apr. 2026, https://4ort.xyz/entity/ramallo-q397099.
BibTeX @misc{4ortxyz_ramallo-q397099_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Ramallo}}, year = {2026}, url = {https://4ort.xyz/entity/ramallo-q397099}, note = {Accessed: 2026-04-10}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Ramallo — https://4ort.xyz/entity/ramallo-q397099 (retrieved 2026-04-10)

Canonical URL: https://4ort.xyz/entity/ramallo-q397099 · Last refreshed: