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Q48491488

episode of the series Kaamelott
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Q48491488

Summary

Q48491488 is a television series episode[1].

Key Facts

  • Q48491488's instance of is recorded as television series episode[2].
  • Spangenhelm is named after Q48491488[3].
  • Q48491488's follows is recorded as Q48491454[4].
  • Q48491488's followed by is recorded as Q48491518[5].
  • Q48491488's part of the series is recorded as Kaamelott[6].
  • Q48491488's IMDb ID is recorded as tt1416227[7].
  • Q48491488's original language of film or TV show is recorded as French[8].
  • Q48491488's title is recorded as Spangenhelm[9].
  • Q48491488's season is recorded as Kaamelott, season 2[10].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.
  5. [6] ↑ . wikidata.org.
  6. [7] ↑ . wikidata.org.
  7. [8] ↑ . wikidata.org.
  8. [9] ↑ . wikidata.org.
  9. [10] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Q48491488. Retrieved May 7, 2026, from https://4ort.xyz/entity/q48491488
MLA “Q48491488.” 4ort.xyz Knowledge Graph, 4ort.xyz, 7 May. 2026, https://4ort.xyz/entity/q48491488.
BibTeX @misc{4ortxyz_q48491488_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Q48491488}}, year = {2026}, url = {https://4ort.xyz/entity/q48491488}, note = {Accessed: 2026-05-07}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Q48491488 — https://4ort.xyz/entity/q48491488 (retrieved 2026-05-07)

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