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Skabelon:Robert for årets børne- og familiefilm

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Skabelon:Robert for årets børne- og familiefilm

Summary

Skabelon:Robert for årets børne- og familiefilm is a Wikimedia navigational template[1].

Key Facts

  • Skabelon:Robert for årets børne- og familiefilm's instance of is recorded as Wikimedia navigational template[2].
  • Skabelon:Robert for årets børne- og familiefilm's template has topic is recorded as Robert Award for Best Children's Film[3].

Body

Definition and Type

Skabelon:Robert for årets børne- og familiefilm's instance of is recorded as Wikimedia navigational template[2].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Skabelon:Robert for årets børne- og familiefilm. Retrieved May 7, 2026, from https://4ort.xyz/entity/q26006673
MLA “Skabelon:Robert for årets børne- og familiefilm.” 4ort.xyz Knowledge Graph, 4ort.xyz, 7 May. 2026, https://4ort.xyz/entity/q26006673.
BibTeX @misc{4ortxyz_q26006673_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Skabelon:Robert for årets børne- og familiefilm}}, year = {2026}, url = {https://4ort.xyz/entity/q26006673}, note = {Accessed: 2026-05-07}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Skabelon:Robert for årets børne- og familiefilm — https://4ort.xyz/entity/q26006673 (retrieved 2026-05-07)

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