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Шаблон:Английский язык

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Шаблон:Английский язык

Summary

Шаблон:Английский язык is a Wikimedia navigational template[1].

Key Facts

  • Шаблон:Английский язык's instance of is recorded as Wikimedia navigational template[2].
  • Шаблон:Английский язык's template has topic is recorded as English[3].
  • Шаблон:Английский язык's populates category is recorded as Category:English language[4].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Шаблон:Английский язык. Retrieved May 7, 2026, from https://4ort.xyz/entity/q23038502
MLA “Шаблон:Английский язык.” 4ort.xyz Knowledge Graph, 4ort.xyz, 7 May. 2026, https://4ort.xyz/entity/q23038502.
BibTeX @misc{4ortxyz_q23038502_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Шаблон:Английский язык}}, year = {2026}, url = {https://4ort.xyz/entity/q23038502}, note = {Accessed: 2026-05-07}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Шаблон:Английский язык — https://4ort.xyz/entity/q23038502 (retrieved 2026-05-07)

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