Long's Peak, Colorado, 1874
painting by William Henry Holmes
Press Enter · cited answer in seconds
0 sources
Summary
Long's Peak, Colorado, 1874 is a painting[1].
Key Facts
- Long's Peak, Colorado, 1874 is the creator of William Henry Holmes[2].
- Long's Peak, Colorado, 1874's image is recorded as Long's Peak, Colorado SAAM-1930.12.59 1.jpg[3].
- Long's Peak, Colorado, 1874's image is recorded as William Henry Holmes - Long's Peak, Colorado, 1874 - 1930.12.59 - Smithsonian American Art Museum.jpg[4].
- Long's Peak, Colorado, 1874's instance of is recorded as painting[5].
- Long's Peak, Colorado, 1874's depicts is recorded as mountain[6].
- Long's Peak, Colorado, 1874's depicts is recorded as tree[7].
- Long's Peak, Colorado, 1874's made from material is recorded as watercolor paint[8].
- Long's Peak, Colorado, 1874's collection is recorded as Smithsonian American Art Museum[9].
- Long's Peak, Colorado, 1874's inventory number is recorded as 1930.12.59[10].
- Long's Peak, Colorado, 1874's location is recorded as Smithsonian American Art Museum[11].
- Long's Peak, Colorado, 1874's country of origin is recorded as United States[12].
- +1874-01-01T00:00:00Z marks the founding of Long's Peak, Colorado, 1874[13].
- Long's Peak, Colorado, 1874's title is recorded as Long's Peak, Colorado, 1874[14].
- Long's Peak, Colorado, 1874's height is recorded as {'unit': 'http://www.wikidata.org/entity/Q174728', 'amount': '+17.4625'}[15].
- Long's Peak, Colorado, 1874's width is recorded as {'unit': 'http://www.wikidata.org/entity/Q174728', 'amount': '+25.4'}[16].
- Long's Peak, Colorado, 1874's Smithsonian American Art Museum artwork ID is recorded as 10670[17].
- Long's Peak, Colorado, 1874's copyright status is recorded as public domain[18].
- Long's Peak, Colorado, 1874's Smithsonian resource ID is recorded as saam_1930.12.59[19].
- Long's Peak, Colorado, 1874's Smithsonian ARK ID is recorded as vk78094422b-3a69-413e-af76-0513e23f411a[20].
Body
Works and Contributions
Long's Peak, Colorado, 1874 is the creator of William Henry Holmes[2].