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July 29, 1890

date in Gregorian calendar
Thing july_29 Q69247476

Facts

5 properties
Instance of
July 29, calendar day of a given year[2]
Part of
July 1890[3]
Day of week
Tuesday[5]
Imported from
wholeness_audit_2026-05-02
Point in time
July 29, 1890[4]
🏷️ Also known as
en 29 July 1890 en July 29, 1890 en 1890-07-29 ar 29 يوليو 1890 ar 29 تموز 1890 cs 29. červenec 1890 cs 29. července 1890 de 29. Juli 1890 el 29 Ιουλίου 1890 el 29/7/1890 es 29 de julio de 1890 fa ۲۹ ژوئیه ۱۸۹۰ fi 29. heinäkuuta 1890 fr 29 juillet 1890 hi २९ जुलाई १८९० id 29 Juli 1890 it 29 luglio 1890 ja 1890年7月29日 ko 1890년 7월 29일 pt 29 de julho de 1890

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Summary

July 29, 1890 is a July 29[1].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). July 29, 1890. Retrieved May 3, 2026, from https://4ort.xyz/entity/july-29-1890
MLA “July 29, 1890.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/july-29-1890.
BibTeX @misc{4ortxyz_july-29-1890_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{July 29, 1890}}, year = {2026}, url = {https://4ort.xyz/entity/july-29-1890}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): July 29, 1890 — https://4ort.xyz/entity/july-29-1890 (retrieved 2026-05-03)

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