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Jo Bamford

British heir and businessman
Person human Q111623486
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Jo Bamford

Summary

Jo Bamford is a human[1]. He was born on +1977-01-01T00:00:00Z[2]. He ranks in the top 0.72% of human entities by monthly Wikipedia readership (203 views/month, #7,204 of 1,000,298).[3]

Key Facts

  • Jo Bamford was born on +1977-01-01T00:00:00Z[2].
  • Jo Bamford is recorded as male[4].
  • Jo Bamford's instance of is recorded as human[5].
  • Jo Bamford's Google Knowledge Graph ID is recorded as /g/11rv3m6hj_[6].

Body

Origins and Family

Jo Bamford was born on +1977-01-01T00:00:00Z[2].

Why It Matters

Jo Bamford ranks in the top 0.72% of human entities by monthly Wikipedia readership (203 views/month, #7,204 of 1,000,298).[3]

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [4] ↑ . wikidata.org.
  2. [5] ↑ . wikidata.org.
  3. [2] ↑ . wikidata.org.
  4. [6] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

Aggregate / graph-position facts

  1. [3] ↑ . Wikimedia Foundation. dumps.wikimedia.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). Jo Bamford. Retrieved May 3, 2026, from https://4ort.xyz/entity/jo-bamford
MLA “Jo Bamford.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/jo-bamford.
BibTeX @misc{4ortxyz_jo-bamford_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{Jo Bamford}}, year = {2026}, url = {https://4ort.xyz/entity/jo-bamford}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): Jo Bamford — https://4ort.xyz/entity/jo-bamford (retrieved 2026-05-03)

Canonical URL: https://4ort.xyz/entity/jo-bamford · Last refreshed: