Jane Lloyd

Summary

Jane Lloyd is a human^[1]. She was born on +1848-03-29T00:00:00Z^[2]. She died on +1899-03-18T00:00:00Z^[3].

Key Facts

• Jane Lloyd was born on +1848-03-29T00:00:00Z^[2].
• Jane Lloyd died on +1899-03-18T00:00:00Z^[3].
• Jane Lloyd's father was Thomas Lloyd^[4].
• Jane Lloyd's mother was Emilia Travers^[5].
• Among Jane Lloyd's spouses was Sampson Lloyd^[6].
• A child of Jane Lloyd was Charles Lloyd^[7].
• A child of Jane Lloyd was Thomas Owen Lloyd^[8].
• A child of Jane Lloyd was Emma Lloyd^[9].
• A child of Jane Lloyd was Eva Lloyd^[10].
• A child of Jane Lloyd was Emilia Lloyd^[11].
• A child of Jane Lloyd was George Lloyd, 1st Baron Lloyd^[12].
• Jane Lloyd's image is recorded as Jane Emilia Lloyd (page 139 crop).jpg^[13].
• Jane Lloyd is recorded as female^[14].
• Jane Lloyd's instance of is recorded as human^[15].
• Jane Lloyd's family name is recorded as Lloyd^[16].
• Jane Lloyd's given name is recorded as Jane^[17].
• Jane Lloyd's given name is recorded as Emilia^[18].
• Jane Lloyd's Geni.com profile ID is recorded as 6000000011555827866^[19].
• Jane Lloyd's Kindred Britain ID is recorded as I20545^[20].
• Jane Lloyd's The Peerage person ID is recorded as p802.htm#i8012^[21].
• Jane Lloyd's SNARC ID is recorded as Rogno^[22].

Body

Origins and Family

Jane Lloyd was born on +1848-03-29T00:00:00Z^[2]. Her father was Thomas Lloyd^[4]. Her mother was Emilia Travers^[5].

Personal Life

Among Jane Lloyd's spouses was Sampson Lloyd^[6]. Children include Charles Lloyd^[7]; Thomas Owen Lloyd^[8], 1873–1960^[23]; Emma Lloyd^[9], 1874–1942^[24]; Eva Lloyd^[10]; Emilia Lloyd^[11], b. 1878^[25]; and George Lloyd, 1st Baron Lloyd^[12], a diplomat^[26], 1879–1941^[27], of United Kingdom^[28], awarded the Distinguished Service Order^[29].

Death and Burial

Jane Lloyd died on +1899-03-18T00:00:00Z^[3].

FAQs

Who were Jane Lloyd's parents?

Jane Lloyd's father was Thomas Lloyd^[4]. Jane Lloyd's mother was Emilia Travers^[5].

Who was Jane Lloyd married to?

Jane Lloyd's spouses include Sampson Lloyd^[6].