Frances Coke
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Frances Coke
Summary
Frances Coke is a human[1]. She was born on January 1, 1599[2]. She passed away in Oxford[3]. She died on January 1, 1645[4]. She ranks in the top 0.73% of human entities by monthly Wikipedia readership (73 views/month, #7,289 of 1,000,298).[5]
Key Facts
- Frances Coke died in Oxford[3].
- Frances Coke was born on January 1, 1599[2].
- Frances Coke was born on August 1602[6].
- Frances Coke was born on 1602[7].
- Frances Coke died on January 1, 1645[4].
- Frances Coke's father was Edward Coke[8].
- Frances Coke's mother was Elizabeth Hatton[9].
- Among Frances Coke's spouses was John Villiers, 1st Viscount Purbeck[10].
- A child of Frances Coke was Robert Danvers, Viscount Purbeck[11].
- Frances Coke is recorded as female[12].
- Frances Coke's instance of is recorded as human[13].
- Frances Coke's unmarried partner is recorded as Robert Howard[14].
- Frances Coke's given name is recorded as Frances[15].
- Frances Coke's described by source is recorded as Oxford Dictionary of National Biography[16].
- Frances Coke's languages spoken, written or signed is recorded as English[17].
- Frances Coke's date of burial or cremation is recorded as June 4, 1645[18].
Body
Origins and Family
Recorded date of birth include January 1, 1599[2], August 1602[6], and 1602[7]. Frances Coke's father was Edward Coke[8]. Her mother was Elizabeth Hatton[9].
Personal Life
Frances Coke was married to John Villiers, 1st Viscount Purbeck[10]. A child of her was Robert Danvers, Viscount Purbeck[11].
Death and Burial
Frances Coke died on January 1, 1645[4]. She passed away in Oxford[3].
Why It Matters
Frances Coke ranks in the top 0.73% of human entities by monthly Wikipedia readership (73 views/month, #7,289 of 1,000,298).[5]
FAQs
Where did Frances Coke die?
Frances Coke died in Oxford[3].
Who were Frances Coke's parents?
Frances Coke's father was Edward Coke[8]. Frances Coke's mother was Elizabeth Hatton[9].
Who was Frances Coke married to?
Frances Coke's spouses include John Villiers, 1st Viscount Purbeck[10].