Eliza Callaghan

Summary

Eliza Callaghan is a human^[1]. Her place of birth was England^[2]. She was born on +1828-01-01T00:00:00Z^[3]. She died in Randwick^[4]. She died on +1915-08-10T00:00:00Z^[5].

Key Facts

• Eliza Callaghan's place of birth was England^[2].
• Eliza Callaghan passed away in Randwick^[4].
• Eliza Callaghan was born on +1828-01-01T00:00:00Z^[3].
• Eliza Callaghan died on +1915-08-10T00:00:00Z^[5].
• Eliza Callaghan's father was Samuel Milford^[6].
• Eliza Callaghan was married to Thomas Callaghan^[7].
• Eliza Callaghan is recorded as female^[8].
• Eliza Callaghan's instance of is recorded as human^[9].
• Eliza Callaghan's family name is recorded as Milford^[10].
• Eliza Callaghan's family name is recorded as Callaghan^[11].
• Eliza Callaghan's given name is recorded as Eliza^[12].
• Eliza Callaghan's NLA Trove people ID is recorded as 1535004^[13].
• Eliza Callaghan's sibling is recorded as Herman George Milford^[14].
• Eliza Callaghan's sibling is recorded as Henry Milford^[15].
• Eliza Callaghan's sibling is recorded as Sussex Charles Milford^[16].
• Eliza Callaghan's sibling is recorded as Frederick Milford^[17].
• Eliza Callaghan's People Australia ID is recorded as 14645^[18].
• Eliza Callaghan's Obituaries Australia ID is recorded as callaghan-eliza-14645^[19].
• Eliza Callaghan's Women Australia ID is recorded as callaghan-eliza-14645^[20].

Body

Origins and Family

Eliza Callaghan's place of birth was England^[2]. She was born on +1828-01-01T00:00:00Z^[3]. Her father was Samuel Milford^[6].

Personal Life

Eliza Callaghan was married to Thomas Callaghan^[7].

Death and Burial

Eliza Callaghan died on +1915-08-10T00:00:00Z^[5]. She passed away in Randwick^[4].

FAQs

Where was Eliza Callaghan born?

Born in England^[2], Eliza Callaghan…

Where did Eliza Callaghan die?

Eliza Callaghan passed away in Randwick^[4].

Who were Eliza Callaghan's parents?

Eliza Callaghan's father was Samuel Milford^[6].

Who was Eliza Callaghan married to?

Eliza Callaghan's spouses include Thomas Callaghan^[7].