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December 29, 1890

date in Gregorian calendar
Thing december_29 Q69247698

Facts

5 properties
Instance of
December 29, calendar day of a given year[2]
Part of
December 1890[3]
Day of week
Monday[5]
Imported from
wholeness_audit_2026-05-02
Point in time
December 29, 1890[4]
🏷️ Also known as
en 29 December 1890 en December 29, 1890 en 1890-12-29 ar 29 كانون الأول 1890 ar 29 ديسمبر 1890 cs 29. prosinec 1890 cs 29. prosince 1890 de 29. Dezember 1890 el 29 Δεκεμβρίου 1890 el 29/12/1890 es 29 de diciembre de 1890 fa ۲۹ دسامبر ۱۸۹۰ fi 29. joulukuuta 1890 fr 29 décembre 1890 hi २९ दिसम्बर १८९० id 29 Desember 1890 it 29 dicembre 1890 ja 1890年12月29日 ko 1890년 12월 29일 pt 29 de dezembro de 1890

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Summary

December 29, 1890 is a December 29[1].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). December 29, 1890. Retrieved May 3, 2026, from https://4ort.xyz/entity/december-29-1890
MLA “December 29, 1890.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/december-29-1890.
BibTeX @misc{4ortxyz_december-29-1890_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{December 29, 1890}}, year = {2026}, url = {https://4ort.xyz/entity/december-29-1890}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): December 29, 1890 — https://4ort.xyz/entity/december-29-1890 (retrieved 2026-05-03)

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