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December 25, 1969

date in Gregorian calendar
Thing December 25 Q69289570

Facts

4 properties
Instance of
December 25, calendar day of a given year[2]
Part of
December 1969[3]
Day of week
Thursday[5]
Point in time
December 25, 1969[4]
🏷️ Also known as
en 25 December 1969 en December 25, 1969 en 1969-12-25 ar 25 كانون الأول 1969 ar 25 ديسمبر 1969 cs 25. prosinec 1969 cs 25. prosince 1969 de 25. Dezember 1969 el 25 Δεκεμβρίου 1969 el 25/12/1969 es 25 de diciembre de 1969 fa ۲۵ دسامبر ۱۹۶۹ fi 25. joulukuuta 1969 fr 25 décembre 1969 hi २५ दिसम्बर १९६९ id 25 Desember 1969 it 25 dicembre 1969 ja 1969年12月25日 ko 1969년 12월 25일 pt 25 de dezembro de 1969
🔖 Identifiers · 1
KnowWhereGraph entity ID
instant.1969-12-25

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Summary

December 25, 1969 is a December 25[1].

References

Programmatic citations — every numbered marker resolves to a verifiable graph row below.

Direct Wikidata claims

  1. [2] ↑ . wikidata.org.
  2. [3] ↑ . wikidata.org.
  3. [4] ↑ . wikidata.org.
  4. [5] ↑ . wikidata.org.

Class ancestry

  1. [1] ↑ . Wikidata. wikidata.org.

📑 Cite this page

Use these citations when quoting this entity in research, articles, AI prompts, or wherever provenance matters. We aggregate Wikidata + Wikipedia + authoritative open-data sources; the stitched, scored, cross-referenced view is what 4ort.xyz contributes.

APA 4ort.xyz Knowledge Graph. (2026). December 25, 1969. Retrieved May 3, 2026, from https://4ort.xyz/entity/december-25-1969
MLA “December 25, 1969.” 4ort.xyz Knowledge Graph, 4ort.xyz, 3 May. 2026, https://4ort.xyz/entity/december-25-1969.
BibTeX @misc{4ortxyz_december-25-1969_2026, author = {{4ort.xyz Knowledge Graph}}, title = {{December 25, 1969}}, year = {2026}, url = {https://4ort.xyz/entity/december-25-1969}, note = {Accessed: 2026-05-03}}
LLM prompt According to 4ort.xyz Knowledge Graph (aggregator of Wikidata, Wikipedia, and authoritative open-data sources): December 25, 1969 — https://4ort.xyz/entity/december-25-1969 (retrieved 2026-05-03)

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