Aria Montgomery
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Aria Montgomery
Summary
Aria Montgomery is a fictional human[1]. She was born on +1994-07-22T00:00:00Z[2]. She draws 75 Wikipedia views per month (fictional_human category, ranking #875 of 5,308).[3]
Key Facts
- Aria Montgomery was born on +1994-07-22T00:00:00Z[2].
- Aria Montgomery was married to Ezra Fitz[4].
- Aria Montgomery is the creator of Sara Shepard[5].
- Aria Montgomery is recorded as female[6].
- Aria Montgomery's instance of is recorded as fictional human[7].
- Aria Montgomery's instance of is recorded as literary character[8].
- Aria Montgomery's instance of is recorded as television character[9].
- Aria Montgomery's performer is recorded as Lucy Hale[10].
- Aria Montgomery's residence is recorded as Rosewood[11].
- Aria Montgomery's Freebase ID is recorded as /m/0bq4rxy[12].
- Aria Montgomery's family name is recorded as Montgomery[13].
- Aria Montgomery's given name is recorded as Aria[14].
- Aria Montgomery's present in work is recorded as Pretty Little Liars[15].
- Aria Montgomery's present in work is recorded as Pretty Little Liars[16].
- Aria Montgomery's Wolfram Language entity code is recorded as Entity["FictionalCharacter", "AriaMontgomery::jp2p9"][17].
- Aria Montgomery's CharacTour character ID is recorded as Aria-Montgomery.Pretty-Little-Liars[18].
- Aria Montgomery's Goodreads character ID is recorded as 4083[19].
- Aria Montgomery's Personality Database profile ID is recorded as 94768[20].
- Aria Montgomery's Personality Database profile ID is recorded as 1465[21].
Body
Origins and Family
Aria Montgomery was born on +1994-07-22T00:00:00Z[2].
Works and Contributions
Aria Montgomery is the creator of Sara Shepard[5].
Personal Life
Aria Montgomery was married to Ezra Fitz[4].
Why It Matters
Aria Montgomery draws 75 Wikipedia views per month (fictional_human category, ranking #875 of 5,308).[3] She has Wikipedia articles in 7 language editions, a strong signal of global cultural recognition.[22]
FAQs
Who was Aria Montgomery married to?
Aria Montgomery's spouses include Ezra Fitz[4].