Sir George Duckworth-King, 6th Baronet

Summary

Sir George Duckworth-King, 6th Baronet is a human^[1]. He was born on +1891-06-08T00:00:00Z^[2]. He died on +1952-02-21T00:00:00Z^[3].

Key Facts

• Sir George Duckworth-King, 6th Baronet was born on +1891-06-08T00:00:00Z^[2].
• Sir George Duckworth-King, 6th Baronet died on +1952-02-21T00:00:00Z^[3].
• Sir George Duckworth-King, 6th Baronet's father was Sir Dudley Duckworth-King, 5th Baronet^[4].
• Sir George Duckworth-King, 6th Baronet's mother was Eva Gore^[5].
• Among Sir George Duckworth-King, 6th Baronet's spouses was Barbara Scott-Makdougall^[6].
• A child of Sir George Duckworth-King, 6th Baronet was Anne Duckworth-King^[7].
• A child of Sir George Duckworth-King, 6th Baronet was Caroline Duckworth-King^[8].
• Sir George Duckworth-King, 6th Baronet is recorded as male^[9].
• Sir George Duckworth-King, 6th Baronet's instance of is recorded as human^[10].
• Sir George Duckworth-King, 6th Baronet's honorific prefix is recorded as Sir^[11].
• Sir George Duckworth-King, 6th Baronet's given name is recorded as George^[12].
• Sir George Duckworth-King, 6th Baronet's The Peerage person ID is recorded as p41702.htm#i417018^[13].

Body

Origins and Family

Sir George Duckworth-King, 6th Baronet was born on +1891-06-08T00:00:00Z^[2]. His father was Sir Dudley Duckworth-King, 5th Baronet^[4]. His mother was Eva Gore^[5].

Personal Life

Sir George Duckworth-King, 6th Baronet was married to Barbara Scott-Makdougall^[6]. Children include Anne Duckworth-King^[7] and Caroline Duckworth-King^[8], b. 1916^[14], of United Kingdom^[15].

Death and Burial

Sir George Duckworth-King, 6th Baronet died on +1952-02-21T00:00:00Z^[3].

FAQs

Who were Sir George Duckworth-King, 6th Baronet's parents?

Sir George Duckworth-King, 6th Baronet's father was Sir Dudley Duckworth-King, 5th Baronet^[4]. Sir George Duckworth-King, 6th Baronet's mother was Eva Gore^[5].

Who was Sir George Duckworth-King, 6th Baronet married to?

Sir George Duckworth-King, 6th Baronet's spouses include Barbara Scott-Makdougall^[6].